Question

if a=b^2x,b=c^2y,c=a^2z,prove that xyz=1÷8

Answer 1

put a= b^2 x in c=a^2z

c = ( b^2 x)^2z
c= b ^4zx

put c = b^4Zx IN b = c^2y

b = (b^4zx)^2y
b = b ^ 8zxy


SO 8 zyx = 1

xyz = 1/8