Question

if a:b = 3:1 and b:c = 5:1 then find the value of( 1) a cube/15bsquare c (2) a square/7bc. please give me answer.

Answer 1

a:b:c=15:5:1
a=15x
b=5x
c=x
(1). 15×15×15/(15×5×5×1)=9
(2). 15×15/(7×5×1) = 45/7

Answer 2

a³ / (15b²c)  = 9  & a²/7bc = 45/7  if a:b = 3:1 and b:c = 5:1

Step-by-step explanation:

if a:b = 3:1 and b:c = 5:1

Let say c  = K

then b = 5K   as b : c = 5:1

a : b = 3:1

=> a : 5K = 3 : 1

=> a = 15K

a = 15K

b = 5K

c = K

a³ / (15b²c)  

= (15K)³ /(15 (5K)²K )

= 15 * 15 * 15 K³ / ( 15 * 5 * 5 * K³)

= 3 * 3

= 9

a³ / (15b²c)  = 9

a²/7bc

= (15K)²/(7(5K)(K)

= 15 * 15 * K² / ( 7 * 5 * K²)

= 15 * 3 / 7

= 45/7

a²/7bc = 45/7

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