If a-b√3 = 2-√3/2+√3, find the value of a and b
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Answered by
3
Step-by-step explanation:
a - b√3
= ( 2-√3)/(2+√3)
= [(2-√3)(2-√3)]/[(2+√3)(2-√3)]
= (2-√3)²/[2²-(√3)²]
= [2²-2×2×√3+(√3)²]/(4-3)
= 4 - 4√3 + 3
= 7 - 4√3
Therefore ,
a - b√3 = 7 - 4√3
a = 7 , b = 4
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Answered by
1
2-√3 / 2+√3
multiply 2-√3 to the numerator and denominator
(2-√3)(2-√3) / (2+√3)(2-√3)
(4+3-4√3) / (4-3)
(7-4√3) / 1
7-4√3.............(1)
Given equation is
a-b√3..............(2)
Equating equation (1) and (2), we get
a = 7 and b = 4
Hope my answer is helpful..
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