Question

If a:b=3:4 and c:d=2:3, then find a3c2+b3d2/ab2d2+a2bcd

Answer 1

Answer:

If a:b=3:4 and c:d=2:3

therefore, a=3,b=4,c=2 and d=3

then,

3×3×2×2+4×3×3×2/3×4×2×3×2+3×2×4×2×3

=36+72/144+144

=108/122

=0.375