Math, asked by tmrajyt, 8 months ago

If A:B=3:5 and B:C=10:13 , find A:B:C.



WITH SOLUTIONS​

Answers

Answered by ramangoyal146200848
1

Answer:

A: B = 3: 5 and B: C = 10: 13

HCF of 3 and 5 is 1 = (3/5)

Then, B: C= (10 ÷ 2)/ (13 ÷ 2)

B: C = 5: (13/2) ∴ A: B: C = 3: 5: (13/2)

A: B: C = 6: 10: 13

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Answered by av7319080
0

Answer:

A : B : C = 10 : 15 : 21

step by step explanation :

Here is a logic

A : B = 3 : 5

B : C = 10 : 13

Then, focus on second B

of which the value is 10. So,

we have to multiply 10 first with 3 to find the value A in the ratio of A : B : C which comes 30 and then multiply 10 with 5 to find the value of B which comes 50 and the last step is multiply the 13 with 5 which comes 65 to find the value of C.

Now, put these value in A : B : C

So, it is A : B : C = 10 : 15 : 21

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