Question

If a - b = 3 and a2 + b2 = 29, find the value of ab. A. 10 b. 12 c. 15 d. 18

Answer 1

given

a-b=3 eq1 and a²+b²=29

then

(a+b)²=29

a+b=√29

a+b=5.38 eq2

then

a-b=3

a+b=5.38

—————

2a=8.38

a=4.19

subtitute a=4.19 in eq 1

a-b=3

4.19-b=3

-b=3-4.19

b=1.19

hope it help to u!!!

Answer 2

The value of ab is 10.

Step-by-step explanation:

Given : If $a-b=3$  and $a^2 + b^2 = 29$

To find : The value of ab ?

Solution :

Using the algebraic identity,

$(a-b)^2=a^2+b^2-2ab$

Substituting the given values,

$a-b=3$  and $a^2 + b^2 = 29$

$(3)^2=29-2ab$

$9=29-2ab$

$2ab=29-9$

$2ab=20$

$ab=\frac{20}{2}$

$ab=10$

Therefore, the value of ab is 10.

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