If a-b=3 and a2+b2=29 find the value of at
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a-b = 3
a= b+3
then
(b+3)2 + b2= 29
b2 +9+6b +b2 =29
2b2 +6b+9-29=0
2b2+6b-20=0
b2+3b-10=0
b2+5b-2b -10 =0
b(b+5)-2(b+5)=0
(b+5)(b-2)=0
b= 2, -5
answer
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