If a-b=3, and ab=10,find:a^3-b^3.
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1
Answer:
117
Step-by-step explanation:
ab=10
a=10/b
then a-b=3 will become 10/b - b=3 by substituting above value of b
after calculating we get the value of b as
b= -5 and a= -2 , for b= 2 and a= 5
then putting these values in a^3 - b^3 we get 117 in any case
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Answer:
a – b = 3
⇒ (a – b)3 = (3)3
⇒ a3 – b3 – 3ab (a –b) = 27
⇒ a3 – b3 – 3 × 10 (3) = 27
⇒ a3 – b3 – 90 = 27
⇒ a3 – b3 = 27 + 90
⇒ a3 – b3 = 117
Alternative Method :
(a –b)3 = a3 – b3 – 3ab (a –b)
⇒ (3)3 = a3 – b3 – 3 × 10 (3)
⇒ 27 = a3 – b3 – 90
⇒ 27 + 90 = a3 – b3
⇒ 117 = a3 – b3
⇒ a3 – b3 = 117
Step-by-step explanation:
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