if a-b=3 and ab=4,find the values of a³-b³??
Answers
Answered by
18
Answer:
hey frnd here is your answer
Step-by-step explanation:
here we will us formula-
a³-b³=(a-b)³+3ab(a-b).
we have values a-b=3 and ab=4.So now put value in formual ,we get
a³-b³=(a-b)³+3ab(a-b)
= (3)³+3(4)(3)
=27+36
a³-b³=63.
So frnd your final answer is 63.
I hope u get your answer
thnx for asking
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Answered by
2
a-b = 3 ---- eq.1
a = b+3,
ab = 4-------eq. 2
(b+3)b = 4
b^2 +3b = 4
b^2+3b-4 = 0
b^2-1b+4b-4 = 0
b(b-1)+4(b-1) = 0
(b+4)(b-1) = 0
b+4 = 0 b-1 = 0
b = -4 b = 1
Substitute b = 1 in eq.1
a-b = 3
a-1 = 3
a = 3+1
a = 4
a^3-b^3 = 4^3-1^3
=64-1
=63
Therefore, a^3-b^3 = 63
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