Math, asked by muktayogesh2007, 2 months ago

if a-b=3 and ab=40 find value of a^2+b^2​

Answers

Answered by rahulkumar9521
0

Answer:

follow the identity

That is,

(a - b)2 = a2 +b2 -2ab

Step-by-step explanation:

(3)2 = a^2+ b^2 - 2*40

9= a^2+ b^2 -80

a^2 + b^2 = 89

Answered by harshraj29126
0

Answer:

a square + b square

we know that (a-b)^2=a^2 +b^2-2ab

==», a^2+b^2=(a-b)^2+2ab

==»a^2+b^2=3^2+2 × 40

==» a^2+b^2= 9+80

==»a^2+b^2=89 Ans.

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