if a-b=3 and ab=40 find value of a^2+b^2
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Answered by
0
Answer:
follow the identity
That is,
(a - b)2 = a2 +b2 -2ab
Step-by-step explanation:
(3)2 = a^2+ b^2 - 2*40
9= a^2+ b^2 -80
a^2 + b^2 = 89
Answered by
0
Answer:
a square + b square
we know that (a-b)^2=a^2 +b^2-2ab
==», a^2+b^2=(a-b)^2+2ab
==»a^2+b^2=3^2+2 × 40
==» a^2+b^2= 9+80
==»a^2+b^2=89 Ans.
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