Question

if a=b^3x, b=c^3y and c=a^3z, then find the value of xyz.

can anyone tell me the answer.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$xyz=\frac{1}{27}$

Step-by-step explanation:

According to the question , $a=b^{3x} , b=c^{3y} , c=a^{3z}$.

We need to find the value of xyz. For that we need to find the value of x , y , z from the 3 equations that we have in the question. We need to know the property of log to find the exact value of the xyz.

Firstly we find the value of x , y , z separately.

$a=b^{3x} \\ or , 3x=log _{b}a \\b=c^{3y}\\ or , 3y = log _{c}b\\ c=a^{3z}\\or , 3z= log _{a}c$

Now we multiply the 3 equations so we find then

$27xyz=1\\or , xyz=\frac{1}{27}$

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