Question

if a/b=4/3 then 3a+2b/3a-2b=?

Answer 1

Step-by-step explanation:

given :

a/b= 4/3

3a+2b/3a-2b

3(4)+2(3)/3(4)-2(3)

12+6/12-6

12+0.5-6

12.5-6

6.5

Answer 2

If a/b = 4/3 then  $\frac{3a+2b}{3a-2b} = 3$

Solution:

Given that,

$\frac{a}{b} = \frac{4}{3}$

To find:

$\frac{3a+2b}{3a-2b}$

Multiply numerator and denominator by 1/b

$\frac{\frac{1}{b} \times (3a+2b)}{\frac{1}{b} \times( 3a-2b)}\\\\Simplify\\\\\frac{ 3 \frac{a}{b} + 2 } { 3 \frac{a}{b} - 2 }\\\\Substitute\ \frac{a}{b} = \frac{4}{3} \\\\\frac{ 3 \times \frac{4}{3} + 2 } { 3 \times \frac{4}{3} - 2 }\\\\\frac{ 4 + 2 }{4 - 2 }\\\\\frac{6}{2} = 3$

Thus $\frac{3a+2b}{3a-2b} = 3$

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