if (a - b) = 4, a2 + b2 = 40, then find as-b3
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Answer:
a^3-b^3=96
Step-by-step explanation:
(a-b)^2=a^2-2ab+b^2
4^2=40-2ab
8=40-2ab
-2ab=-32
ab=-32/-2
ab=16
a^3-b^3=(a-b)(a^2+b^2-ab)
=4(40-16)
=4x24
=96
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