If a-b=4 and a+b=6,find:a^2+b^2 and ab
Answers
Answered by
2
Hii mate ☺
Answer:
26 nd 5 respectively
Step-by-step explanation:
a-b=4
a+b=6
______
2a=10
a=5
a+b =6
5+b=6
b=6-5
b=1
Now the value of ab is 5×1=5
nd value of a^2+b^2 is
5^2+1^2
25+1
=26
Hope it helps you ☺✌✌
tsumisaron:
np
Answered by
1
add the equation first.....
a - b = 4
a + b = 6
a - b + a + b = 6 + 4
a + a = 10
2a = 10
a = 10 / 2
a = 5
so,
as we have
a + b = 6
5 + b = 6
b = 6 - 5
b = 1
and also we have...
a - b = 4
5 - b = 4
5 - 4 = b
1 = b
so at last we get the value of
a = 5
b = 1
so....
= a² + b²
= (5)² + (1)²
= 25 + 1
= 26
and ab
= a * b
= 5 * 1
= 5
a - b = 4
a + b = 6
a - b + a + b = 6 + 4
a + a = 10
2a = 10
a = 10 / 2
a = 5
so,
as we have
a + b = 6
5 + b = 6
b = 6 - 5
b = 1
and also we have...
a - b = 4
5 - b = 4
5 - 4 = b
1 = b
so at last we get the value of
a = 5
b = 1
so....
= a² + b²
= (5)² + (1)²
= 25 + 1
= 26
and ab
= a * b
= 5 * 1
= 5
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