Math, asked by tsumisaron, 1 year ago

If a-b=4 and a+b=6,find:a^2+b^2 and ab

Answers

Answered by Anonymous
2

Hii mate ☺


Answer:


26 nd 5 respectively


Step-by-step explanation:


a-b=4

a+b=6

______

2a=10

a=5


a+b =6

5+b=6

b=6-5

b=1



Now the value of ab is 5×1=5


nd value of a^2+b^2 is

5^2+1^2

25+1

=26




Hope it helps you ☺✌✌


tsumisaron: np
Answered by neanumha
1
add the equation first.....

a - b = 4
a + b = 6

a - b + a + b = 6 + 4
a + a = 10
2a = 10
a = 10 / 2
a = 5

so,
as we have
a + b = 6
5 + b = 6
b = 6 - 5
b = 1


and also we have...
a - b = 4
5 - b = 4
5 - 4 = b
1 = b


so at last we get the value of
a = 5
b = 1

so....
= a² + b²
= (5)² + (1)²
= 25 + 1
= 26

and ab
= a * b
= 5 * 1
= 5

shivkumar34: hiii
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