Question

if a-b=4 and a+b=6 find i. a2+b2 ii. ab​

Answer 1

Answer:

a+b=6

(a+b)  

2

=36 __(1)

a−b=4

(a−b)  

2

=16 __(2)

adding (1) & (2) we get

(a+b)  

2

+(a−b)  

2

=a  

2

+b  

2

+2ab+a  

2

+b  

2

−2ab=52

2(a  

2

+b  

2

)=52

a  

2

+b  

2

=56

a+b=6 __(1)

a−b=4 __(2)

____________

   2a=10

a=5

Substitute a=5 in any of equations (1) & (2)

5+b=6

b=1

ab=(5)(1)

=5

Step-by-step explanation:

Answer 2

Step-by-step explanation:

a - b=4 ( eq1)

a + b=6. (eq2)

u should add eq 1 and eq 2both bs will cancel as one is having + symbol and the other is having -(minus) symbol

then u get 2a= 10

a= 10/2

a=5

now substitute this a in eq 2

a+b=6

5+b=6

b=6-5

b=1

now let's come back to our question

1 a2+ b2 = a2+2ab +b2 ( formula)

now a is 5 and bis 1 let's substitute it

answer is 25+ 2(5*1)+1

that is 25+ 11 which is equal to 36

second ab = 5*1 = 5

so answer 1 is 36 answer 2 is 5

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