If a+b = 4 and ab= -12, find 1) a-b
2) a^2 - b^2
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Answered by
1
Answer:
Given,
a+b=3 ,
a-b=2,
(a+b)^2=a^2+b^2+2ab————-(1)
(a-b)^2=a^2–2ab+b^2————(2)
(1)-(2)=>(a+b)^2-(a-b)^2=2(a^2+b^2)
=>(3)^2-(2)2=2(a^2+b^2)
=>6–4=2(a^2+b^2)
=>2=2(a^2+b^2)
the value of 2 (a^2+b^2) is 2
Answered by
1
Answer:
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