If a+ b = 4 and ab =(-12) then find a- b and a²- b²ind a- b and a²- b²hen find
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Answered by
0
Answer:
a-b=8
Step-by-step explanation:
a=6 b=-2
a-b= 6-(-2) = 6+2= 8
a∧2- b^2 = (a-b)∧2
(6+2)^2
now using the identity we get 36+24+4 = 64
Answered by
0
Answer:
a+b=4
a=4-b - - - - - - - - - equation1
Substitute a in the product of a and b
(4-b)*b=-12
4b-b*b=-12
=b^2-4b-12
By factorisation we have two values for b
b-6=0| b+2=0
b=6|b=-2
negative value cannot be the factor
So b=6
Substitute b in equation 1
a=4-6
a=-2
a-b=-2-6
=-8
a^2-b^2=(-2)^2-(6)^2
=4-36
=-32
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