IF a +b=4 and ab=3, Find
the value of a^2 +b^2
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Answered by
1
Answer:
Given: a +b=4, ab=3
so,
[a+b]^2 = [4]^2
a^2+2ab+b^2 = 16
a^2+b^2+2[3] = 16
a^2+b^2+6 = 16
a^2+b^2 = 16-6
a^2+b^2 = 10
Answered by
0
Answer:
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my answer is that only
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