If a+b=4 and ab=3 find the value of a³+b³
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Given:-
a+b=4
ab=3
To find:-
Value of a³+b³
Solution:-
We know that (a+b)³=a³+b³+3ab(a+b)
So,by cubing both the sides in equation a+b=4,we get-----
(a+b)³=(4)³
=>a³+b³+3ab(a+b)=64
Now,by substituting the values of ab and a+b,we get----
=>a³+b³+3×3(4)=64
=>a³+b³+36=64
=>a³+b³=64-36
=>a³+b³=28
Thus,the value of a³+b³ is 28.
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