Question

if A+B = π/4. Prove that (Cot A-1) (Cot B-1)= 2​

Answer 1

Answer:

cot(A+B)=

cotA+cotB

cotAcotB−1

=1 {∵cot(π/4)=1}

cotAcotB−1=cotA+cotB

cotA+cotB−cotAcotB−1=−1−1

(1−cotA)(1−cotB)=−2

(cotA−1)(cotB−1)=2.

Step-by-step explanation:

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