If a+b=45° then prove that (1+tana)(1+tanb)=2 hence find tan (45/2)
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Given A+B=45
{Take tan on both the sides }
tan(A+B) = tan45
tanA+tanB/1- tanA tanB = 1
tanA+tanB=1-tanA.tanB
tanA+tanB+tanA.tanB=1
adding "1" on both sides
1+ tanA+tanB+tanA.tanB=1+1
(1 + tanA)+tanB(1+tanA).=2
(1+tanA)(1+tanB)=2 Hence proved .
hope it's help u
{Take tan on both the sides }
tan(A+B) = tan45
tanA+tanB/1- tanA tanB = 1
tanA+tanB=1-tanA.tanB
tanA+tanB+tanA.tanB=1
adding "1" on both sides
1+ tanA+tanB+tanA.tanB=1+1
(1 + tanA)+tanB(1+tanA).=2
(1+tanA)(1+tanB)=2 Hence proved .
hope it's help u
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