Question

If a boy takes as much time in running 10 m as a car in covering 25 m, then find the distance covered by the boy during the time the car covers 1 km

Answer 1

let distance covered by boy is B
let distance covered by car is C
then B/C = 10/25=2/5
then we will get 5B=3C
as C = 1km = 1000m
5×B = 3×1000
B = 400m

Answer 2

The distance covered by the boy is 400 m during the time the car covers a distance of 1 km.

• A boy takes the same time in running 10 m as a car covering a distance of 25 m.

• We have to find the distance covered by the the boy during the time the car covers a distance of 1 km that is 1000m.
• The distance covered by the boy and the car are in proportion as the speed does not change.
• Ratio of the distances covered is

$\frac{D_{boy}{D_{car}}$ = $\frac{10}{25}$

$\frac{D_{boy}{D_{car}}$ = $\frac{2}{5}$

• Now to find the distance covered by the boy when car covers a distance of 1 km.

$\frac{D_{boy}{D_{car}}$ = $\frac{2}{5}$

$\frac{D_{boy}{1000}$ = $\frac{2}{5}$

$D_{boy}$ = 400

• Distance covered by the boy is 400 m.