Math, asked by Anonymous, 7 months ago

If A+B=45°than show that (1+tanA)(1+tanB)=2 explain in telugu

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Answered by KhataranakhKhiladi2

Step-by-step explanation:

A+B=45°.

so Tan(A+B) = 1

so (Tan A + Tan B )/(1-Tan A ×Tan B) = 1.

Take the denominator to the other side and rearrange the factor on the RHS.

so Tan A + Tan B + Tan A × Tan B = 1

Add 1 on both sides and factorize the LHS to get

(1+Tan A) (1+Tan B) = 2.

proved.

Answered by sundramgautam5

Answer:

A+B=45°.

so Tan(A+B) = 1

so (Tan A + Tan B )/(1-Tan A ×Tan B) = 1.

Take the denominator to the other side and rearrange the factor on the RHS.

so Tan A + Tan B + Tan A × Tan B = 1

Add 1 on both sides and factorize the LHS to get

(1+Tan A) (1+Tan B) = 2.

proved.

done.

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Given that,

To Prove

Now,

Adding one on both sides,we get :

Henceforth,Proved

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If A+B=45°than show that (1+tanA)(1+tanB)=2 explain in telugu ​

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If A+B=45°than show that (1+tanA)(1+tanB)=2 explain in telugu