Question

If a/b=5/3 then find ratio of a+7b/7b

Answer 1

Answer: $\frac{a+7b}{7b} = \frac{26}{21}$

Step-by-step explanation:

$\frac{a}{b} = \frac{5}{3}\\\\3a = 5b\\\\a = \frac{5b}{3}$

Substituting this value of a in the second expression, we get

$\frac{a+7b}{7b} = \frac{\frac{5b}{3} + 7b}{7b}$

=> $\frac{5b+21b}{21b} = \frac{26b}{21b} = \frac{26}{21}$

Therefore,

$\frac{a+7b}{7b} = \frac{26}{21}$

Please brainlist my answer, if helpful!

Answer 2

Answer:

The value of (a + 7b)/ 7b = 26/21.

Step-by-step explanation:

Given:-

(a/b) = 5/3

or, a = 5k, b = 3k

To find:-

Value of the ratio of (a + 7b)/ 7b = ?

Solution:-

Substitute:

[5k + 7(3k)]/[7(3k)]

=> (5k + 21k)/21k

=> 26k/21k

K will cancel out in both numerator and denomination.

=> 26/21

Hence, the value of (a + 7b)/ 7b = 26/21.