Question

if a:b=5:6 and b:c=7:8, tyen by approximately what percent is c more than a?

Answer 1

Answer:

37.14%

Step-by-step explanation:

a : b = 5 : 6 --------- [ 1 ]

b : c = 7: 8  --------- [ 2 ]

Ratio [ 1 ] x 7:

a : b = 5 x 7  : 6 x 7

a : b = 35 : 42

Ratio [2] x 6 :

b : c = 7 x 6 : 8 x 6

b : c = 42 : 48

Combine the ratios:

a : b : c = 35 : 42 : 48

Find the difference between c more than a:

Difference = 48 - 35 = 13

Percentage difference = 13/35 x 100 = 37.14%

Answer: c is 37.14% more than a

Answer 2

Answer:

37.14% (approx.)

Step-by-step explanation:

Given that : The ratio between 'a' and 'b'

a:b = 5:6

And the ratio between 'b' and 'c'

b:c = 7:8

By the z formula

a:(b1=b2):c = (a×b2):(b2×b1):(b1×c)

Here, b1 = 6 and b2 = 7

=> a:b:c = (5×7):(7×6):(6×8) {b1=b2=b}

=> a:b:c = 35:42:48

Now, the difference between 'a' and 'c' = c–a = 48–35 = 13

Now, 'c' is greater than 'a' = [(c–a)/a] × 100

=> (13/35)×100

=> 1300/35 = 37.14% ( approx )

It means 'c' is 37.14% (approx) is greater than 'a'.

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