Question

if a:b=5:6 and b:c is 18:23, find a:b:c​

Answer 1

Given

a/b = 5/6

So,

a = 5b/6

and

b/c = 18/23

So,

c = 23b/18

So, a : b : c

= 5b/6 : b : 23b/18

Cancel b

→ 5/6 : 1 : 23/18

Multiply each term by 18

→ 15 : 18 : 23.

Answer 2

Question :

if a : b=5 : 6 and b : c is 18 : 23, find a : b : c

Solution :

According to the question, we know that

a : b = 5 : 6

Therefore,

a/b = 5/6

a = 5b/6 -------- (1)

Now,

b : c = 18 : 23

b/c = 18/23

c = 23b/18 -------- (2)

From (1) and (2) we get

$\sf a : b : c = \frac{5b}{6} : b : \frac{23b}{18}$

Now as b is common we need to cancel b

$\sf a :b:c = \frac{5 \cancel b}{6} : \cancel{b}: \frac{23 \cancel b}{18}$

So we get

a : b : c = 5/6 : 1 : 23/18

Now to take do the L.C.M

6 and 18 = 18

$\sf a : b :c = \frac{5 \times 3}{6 \times 3} : \frac{1 \times 18}{1 \times 18} : \frac{23 \times 1}{18}$

So we get,

a : b : c = 15 : 18 : 23

So a : b : c is 15 : 18 : 23

Regards

# BeBrainly