if a:b=5:9 and b:c=4:7, find a:b:c and a:c ?
Explain and answer with detailed steps.
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Answered by
2
we know that,
a:b=5:9
b:c=4:7
so,b is common in both.
so,5:9*4=20:36
4:7*9=36:63
so,36 is common in both which is the value of b.
therefore,
a:b:c=20:36:63 and
a:c=20:63
a:b=5:9
b:c=4:7
so,b is common in both.
so,5:9*4=20:36
4:7*9=36:63
so,36 is common in both which is the value of b.
therefore,
a:b:c=20:36:63 and
a:c=20:63
Answered by
0
Answer:
20:36:63
Step-by-step explanation:
First we find the lcm of the two b's that is 9 and 4.
Lcm of 9 and 4 = 36 = b
Now we multiply 'a' which is 5 with 'b'(in the second ratio) which is 4.
5 X 4 = 20 = a
Then we multiply 'b' ( In the first ratio) which is 9 and 'c' which is 7.
9 X 7 = 63 = c
Now if we arrange it in order we get
a = 20 : b = 36 : c = 63
= 20 : 36 : 63
Thus the answer is 20 : 36 : 63.
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