If a-b=5 and ab=12, find the value of a²+b².
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Given : a - b = 5 and ab = 12
On Squaring, a – b = 5, both sides,
(a – b)² = (5)²
a² + b² – 2ab = 25
[By using the identity, (a – b)² = a² + b² – 2ab]
a² + b² – 2 x 12 = 25
[ab = 12]
a² + b² – 24 = 25
a² + b² = 25 + 24
a² + b² = 49
Hence, the value of a² + b² is 49.
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Answer:
Step-by-step explanation:
On Squaring, a – b = 5, both sides,
(a – b)² = (5)²
a² + b² – 2ab = 25
[By using the identity, (a – b)² = a² + b² – 2ab]
a² + b² – 2 x 12 = 25
[ab = 12]
a² + b² – 24 = 25
a² + b² = 25 + 24
a² + b² = 49
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