Math, asked by Yogesh5824, 10 months ago

If a-b=5 and ab=12, find the value of a²+b².

Answers

Answered by nikitasingh79
1

Given : a - b = 5 and ab = 12

On Squaring, a – b = 5, both sides,

(a – b)² = (5)²

a² + b² – 2ab = 25

[By using the identity, (a – b)² = a² + b² – 2ab]  

a² + b² – 2 x 12 = 25

[ab = 12]

a² + b² – 24 = 25

a² + b² = 25 + 24

a² + b² = 49

Hence, the value of a² + b² is 49.

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Answered by Anonymous
0

Answer:

Step-by-step explanation:

On Squaring, a – b = 5, both sides,

(a – b)² = (5)²

a² + b² – 2ab = 25

[By using the identity, (a – b)² = a² + b² – 2ab]  

a² + b² – 2 x 12 = 25

[ab = 12]

a² + b² – 24 = 25

a² + b² = 25 + 24

a² + b² = 49

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