If a+b=(-5) and ab=(-6) then what is the value of a³-b³ where a>b?
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SOLUTION :-
Given ,
- a + b = - 5 ..eq(1)
- ab = - 6 ..eq(2)
To find ,
- a³ - b³ = ?
✤ Squaring on Both sides for eq(1)
☞ ( a + b )² = ( - 5 )²
☞ a² + b² + 2ab = 25
☞ a² + b² = 25 - 2 ( - 6 )
☞ a² + b² = 25 + 12
☞ a² + b² = 37
♦ ( a - b )² = a² + b² - 2ab = 37 - 12 = 25
♦ ( a - b)² = 25
♦ a - b = √25 = 5
✤ Now , finding a³ - b³
➜ a³ - b³ = ( a - b ) ( a² + b² + ab )
➜ a³ - b³ = 5 [ 37 + (-6) ]
➜ a³ - b³ = 5 [ 37 - 6 ]
➜ a³ - b³ = 5 [ 31 ]
➜ a ³ - b³ = 155
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