If a-b=5,show that a³-b³-15ab=125.
Answers
Answer:
I think given equation means a^3 + b^3 + 15ab = 125 .
It becomes a^3 + b^3 + 15ab - 125 = 0 .
I think you know this identity :
x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 - xy - xz - yz)
Let x = a , y = b and z = -5 . So
a^3 + b^3 - 125 + 15ab = (a + b - 5)(a^2 + b^2 + 25 - ab + 5a + 5b)
Therefore , given equation becomes
(a + b - 5)(a^2 + b^2 + 25 - ab + 5a + 5b) = 0
Case1. a + b - 5 = 0
This means a + b = 5 .
Case2. a^2 + b^2 + 25 - ab + 5a + 5b = 0
We can think
(a + 5)^2 + (b + 5)^2 - (a + 5)(b + 5)
= a^2 + 10a + 25 + b^2 + 10b + 25 - ab - 5a - 5b - 25
= a^2 + b^2 - ab + 5a + 5b + 25
= 0
So let A = a + 5 and B = b + 5 ,
A^2 + B^2 - AB = 0
It is a quadratic equation of B , so
B = (1/2)(A ± √(A^2 - 4A^2))
= (1/2)(A ± √(-3A^2))
A and B must be real , so the solution is A = 0 and B = 0 only .
This means a = -5 and b = -5 , a + b = -10 .
So , a + b = 5 or -10 .
(a + b = -10 only when a = -5 and b = -5 .)