If a-b= 6 and ab = 20 find a³-b³
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Answered by
19
Hey there!
Praneeth from Brainly.in here to help!
Given
➻ ab=20,
➻ (a-b)=6
➟ (a-b)³=a³-b³-3ab(a-b)
➟ (a-b)³=a³-b³-3a²b+3ab²
➟a ³-b³=(a-b)³+3ab(a-b)
➺ 6³+3*20(6)
➺ 216+360
➺ 576
∴a³-b³=576
hope helped!
Praneeth from Brainly.in here to help!
Given
➻ ab=20,
➻ (a-b)=6
➟ (a-b)³=a³-b³-3ab(a-b)
➟ (a-b)³=a³-b³-3a²b+3ab²
➟a ³-b³=(a-b)³+3ab(a-b)
➺ 6³+3*20(6)
➺ 216+360
➺ 576
∴a³-b³=576
hope helped!
Answered by
9
(a-b)³=a³-3ab(a-b)-b³
a^3-b^3= (a-b)^3+3ab(a-b)
=6^3+3×20×6
=216+360
= 576
a^3-b^3= (a-b)^3+3ab(a-b)
=6^3+3×20×6
=216+360
= 576
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