If a-b=6 and ab=20 find the value of a cube minus b cube
Answers
Answered by
19
Answer:
576
Step-by-step explanation:
(a-b)^3 = a^3 -b^3 -3ab(a-b) [identity]
a^3-b^3=(a-b)^3 + 3ab(a-b)
a^3-b^3 =(6)^3 + 3(20)(6)
a^3-b^3 = 216 + 360
a^3-b^3 = 576
Answered by
6
Answer:
576
Step-by-step explanation:
a-b=6
ab=20
a^3-b^3=?
(a-b)^3=a^3-b^3+3ab(a-b)
a^3-b^3=(a-b)^3+3ab(a-b)
=6^3+3×20×6
=216+360
=576
therefore:a^3-b^3=576
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