Math, asked by jahanvisinghsolanki, 6 months ago

if a-b=6 and ab=20 find the value of a³-b³?​

Answers

Answered by Anonymous
6

Step-by-step explanation:

Given,

a-b=6

ab=20

(a-b)³ = a³- b³-3 ab(a-b)

(a-b)³= a³-b³-3a²b+3ab²

a³-b³= (a-b³)+3ab(a-b)

=6³+3*20(6)

= 216+360

= 576

so, a³- b³= 576

Answered by gamershashwatmishra
0

Step-by-step explanation:

answer is 576 ......m..... .

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