Math, asked by dgmp755, 10 months ago

If a+b=6, find the value of a3+b3+18ab-216

Answers

Answered by rani49035

4

Answer:

a+b = 6

cubing both sides

we get

a³ + b³ + 3ab(a+b) = 216

a³ + b³ + 3ab(6) = 216

a³ + b³ + 18ab = 216

a³ + b³ + 18ab -216 = 0

thus the required answer is 0

hope this will help you

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