Question

If A+B=60, A-B=40, then find A/B​

Answer 1

Given - A+B=60

A-B=40

Find - A/B

Solution - Labelling the equations as -

A+B=60 - equation 1

A-B=40 - equation 2

From the equation A+B = 60, we will be taking the value of B.

B = 60 - A

Keeping the value of B in Equation 2.

A - (60 - A) = 40

Solving the above mentioned mathematical expression to find the value of A.

A + A - 60 = 40

2A = 40 + 60

2A = 100

A = 100/2

A = 50

Finding value of B from equation 1

50 + B = 60

Performing subtraction to find the value of B.

B = 10

Now calculating A/B.

A/B = 50/10

A/B = 5

Thus value of A/B = 5

Answer 2

Concept:

An equation is said to be linear if the maximum power of the variable is consistently 1. A one-degree equation is another name for it. A linear equation with one variable has the conventional form Ax + B = 0. In this case, the variables x and A are variables, while B is a constant. A linear equation with two variables has the conventional form Ax + By = C. Here, the variables x and y, the coefficients A and B, and the constant C are all present.

Given information:

A+B=$60$

A-B=$40$

To find:

We need to find the value of A/B.

Solution:

It is given that

A+B=$60$               .......$(1)$

A-B=$40$                .......$(2)$

Use equation (1).

B= $60$ - A

Put the value of B in equation (2).

A - ( $60$ - A) = $40$

A-$60$ + A = $40$

$2$A = $100$

A = $50$

Again put the value of A in equation (1).

$50$+B=$60$

B= $10$

Now,

A/B= $\frac{50}{10}$

     =$5$

Hence the answer is $5$.

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