If A=B=60degree then verify that ,cos (A-B) =cosA cosB +sin A sin B
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since A=B
Cos(A-B) =Cos0=1
CosACosB+SinASinB=Cos^2A+Sin^2A=1
Cos(A-B) =Cos0=1
CosACosB+SinASinB=Cos^2A+Sin^2A=1
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