If a/b = 7/3 then find the value of a^3 - b^3/b^3
please solve I need it.....
Answers
Answered by
7
Hello friend
------------------
Thanks for your question.
=) In example
=) a/b = 7/3 then a/7 = b/3 = k
=) a = 7k, b = 3k
Now we can easily find the value
So let's go,
=) a^3 - b^3/b^3
= (7k)^3 - (3k)^3/(3k)^3
=) 343k^3 -27k^3/27k^3
=) 316k^3/27k^3
=) 316/27
Therefore a^3-b^3/b^3. = 316/27
I hope this will helps you.
keep asking.
Thanks.
------------------
Thanks for your question.
=) In example
=) a/b = 7/3 then a/7 = b/3 = k
=) a = 7k, b = 3k
Now we can easily find the value
So let's go,
=) a^3 - b^3/b^3
= (7k)^3 - (3k)^3/(3k)^3
=) 343k^3 -27k^3/27k^3
=) 316k^3/27k^3
=) 316/27
Therefore a^3-b^3/b^3. = 316/27
I hope this will helps you.
keep asking.
Thanks.
Priyasharma111:
Right answer
Similar questions
Computer Science,
7 months ago
English,
7 months ago
Math,
7 months ago
Science,
1 year ago
Math,
1 year ago