Question

the sides of a triangle 5cm 12cm 13cm. Find the length of the perpendicular from the opposite vertex to the side whose length is 13 cm.

Answer 1

sides of triangle = 5 cm, 12cm, 13cm
let the pependicular = x
5^2 = x^2 + (part of 13 cm side )^2
5^2 - x^2= (part of 13 cm side )^2___1

also 12^2 - x^2= (part of 13 cm side )^2__2

from 1 and 2
we get

5^2 - x^2 = 12^2 - x^2

Answer 2

S is equals to 5 + 12 + 13 / 2 which is equals to15 now area is equals to √ 15* 15 - 5 into 15 - 12 into 15 - 13
√15 *10*3*2
√5*3*5*2*3*2
150
areas equals to 150 centimetre square now area of triangle is equal to one by two into base into height now area is 150 which is equals to half into base which is 13 CM into height which is not given
150=1/2*13*h
150*2/13=h