If a-b =7 and 2ab =45 , find the value of a cube -b cube
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I hope it will be helpful to you.....
A^3-B^3=(a-b)(a^2+ab+b^2)
First we find a^2+b^2
For that (a-b)^2=a^2+b^2+2ab
(7)^2=a^2+b^2+2×45
49=a^2+b^2+90
49-90=a^2+b^2
41=a^2+b^2
Now,
A^3-B^3=(7)(41+45)
a^3-b^3=7×86
a^3-b^3=702.....that is ur answer...
Please mark as brainliest..
A^3-B^3=(a-b)(a^2+ab+b^2)
First we find a^2+b^2
For that (a-b)^2=a^2+b^2+2ab
(7)^2=a^2+b^2+2×45
49=a^2+b^2+90
49-90=a^2+b^2
41=a^2+b^2
Now,
A^3-B^3=(7)(41+45)
a^3-b^3=7×86
a^3-b^3=702.....that is ur answer...
Please mark as brainliest..
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