If a+b=7 and ab=10. find a^2+ b^2
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Answered by
2
a+b=7
ab=10
a=10/b
10/b+b=7
7b-bsq=10
10/7=-b=3.5
a^2+b^2=-7+2b
2b=7
b=7/2
b=3.5
ab=10
a=10/b
10/b+b=7
7b-bsq=10
10/7=-b=3.5
a^2+b^2=-7+2b
2b=7
b=7/2
b=3.5
Answered by
6
Given Equation is a + b = 7 and ab = 10.
(a + b) = 7
Squaring on both sides,
(a + b)^2 = (7)^2
a^2 + b^2 + 2ab = 49
a^2 + b^2 + 2(10) = 49
a^2 + b^2 + 20 = 49
a^2 + b^2 = 49 - 20
a^2 + b^2 = 29.
Hope this helps!
(a + b) = 7
Squaring on both sides,
(a + b)^2 = (7)^2
a^2 + b^2 + 2ab = 49
a^2 + b^2 + 2(10) = 49
a^2 + b^2 + 20 = 49
a^2 + b^2 = 49 - 20
a^2 + b^2 = 29.
Hope this helps!
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