If a-b =7 and ab =8 evaluate i)a²+b² and ii)a+b
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Answered by
0
Answer:
Take the square of both equations.
(a+b) ² =(8) ²
a ² + b² + 2ab =64 (equation 1)
(a-b) ² = (6)²
a² + b² - 2ab = 36 (equation 2)
Now add equation 1 with equation 2
(a ² + b² + 2ab) + (a² + b² - 2ab) = 64 + 36
2a² + 2b² = 100
2(a² + b²) = 100
a² + b² = 50
Answered by
1
(a-b)²= a²-2ab+b²
a-b =7,ab =8
7²=-2(8)+a²+b²
a²+b²=49+16
a²+b²=65
(a+b)²= a²+2ab+b²
(a+b)²=16+65
(a+b)²=81
a+b=9
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