Math, asked by itzsimransingh2, 9 months ago

prove that root 5 is irrational​

Answers

Answered by ItzMADARA
0

Let us assume that √5 is a rational number.

Let us assume that √5 is a rational number.we know that the rational numbers are in the form of p/q form where p,q are intezers.

Let us assume that √5 is a rational number.we know that the rational numbers are in the form of p/q form where p,q are intezers.so, √5 = p/q

Let us assume that √5 is a rational number.we know that the rational numbers are in the form of p/q form where p,q are intezers.so, √5 = p/q p = √5q

Let us assume that √5 is a rational number.we know that the rational numbers are in the form of p/q form where p,q are intezers.so, √5 = p/q p = √5qwe know that 'p' is a rational number. so √5 q must be rational since it equals to p

Let us assume that √5 is a rational number.we know that the rational numbers are in the form of p/q form where p,q are intezers.so, √5 = p/q p = √5qwe know that 'p' is a rational number. so √5 q must be rational since it equals to pbut it doesnt occurs with √5 since its not an intezer

Let us assume that √5 is a rational number.we know that the rational numbers are in the form of p/q form where p,q are intezers.so, √5 = p/q p = √5qwe know that 'p' is a rational number. so √5 q must be rational since it equals to pbut it doesnt occurs with √5 since its not an intezertherefore, p =/= √5q

Let us assume that √5 is a rational number.we know that the rational numbers are in the form of p/q form where p,q are intezers.so, √5 = p/q p = √5qwe know that 'p' is a rational number. so √5 q must be rational since it equals to pbut it doesnt occurs with √5 since its not an intezertherefore, p =/= √5qthis contradicts the fact that √5 is an irrational number

Let us assume that √5 is a rational number.we know that the rational numbers are in the form of p/q form where p,q are intezers.so, √5 = p/q p = √5qwe know that 'p' is a rational number. so √5 q must be rational since it equals to pbut it doesnt occurs with √5 since its not an intezertherefore, p =/= √5qthis contradicts the fact that √5 is an irrational numberhence our assumption is wrong and √5 is an irrational number.

If you satisfy on my answer please mark it BRAINLIEST ✏️✏️✏️✏️✏️✏️✏️

Answered by pushpendra345
0

Answer:

a irrational number is a number which can't be written in the form of p/q(qis not equal to 0).here it can't be written inn this format this it's an irrational nber

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