If a+b = 8 ,a square + b square = 40 find a cube + b cube
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Answered by
9
hello...
a3 + b3 = (a + b)(a2 + b2 - ab)
= (8)(40 - ab)
(a + b)2 (a+b)2 = a2 + b2 + 2ab
(8)2 = 40 + 2ab64 - 40
= 2ab24/2
= abab = 12...(1)
Therefore,a3 +b3 = (8)(40 - 12) ....(from 1)
(8)(28)224.
thank you ☺
a3 + b3 = (a + b)(a2 + b2 - ab)
= (8)(40 - ab)
(a + b)2 (a+b)2 = a2 + b2 + 2ab
(8)2 = 40 + 2ab64 - 40
= 2ab24/2
= abab = 12...(1)
Therefore,a3 +b3 = (8)(40 - 12) ....(from 1)
(8)(28)224.
thank you ☺
NidhraNair:
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Answered by
3
a3 + b3 = (a + b)(a2 + b2 - ab)
= (8)(40 - ab)
To find the value of ab we can find it using the formula of (a + b)2
(a+b)2 = a2 + b2 + 2ab
(8)2 = 40 + 2ab
64 - 40 = 2ab
24/2 = ab
ab = 12...(1)
Therefore,
a3 +b3 = (8)(40 - 12) .....(from 1)
(8)(28)
224.
Hope u found this answer helpful..
= (8)(40 - ab)
To find the value of ab we can find it using the formula of (a + b)2
(a+b)2 = a2 + b2 + 2ab
(8)2 = 40 + 2ab
64 - 40 = 2ab
24/2 = ab
ab = 12...(1)
Therefore,
a3 +b3 = (8)(40 - 12) .....(from 1)
(8)(28)
224.
Hope u found this answer helpful..
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