If A+B=90 and Dec A = 5/3 then find the value of codec B
Answers
Answered by
9
HELLO DEAR,
we know that:-
sec(90-B)=cosecB
given that:-
A+B=90°
=> A= (90°-B)-------(1)
and
secA=5/3
=> sec(90-B)=5/3 --------from (1)
=> cosecA =5/3
I HOPE ITS HELP YOU DEAR,
THANKS
we know that:-
sec(90-B)=cosecB
given that:-
A+B=90°
=> A= (90°-B)-------(1)
and
secA=5/3
=> sec(90-B)=5/3 --------from (1)
=> cosecA =5/3
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by
26
HAI DEAR!!
we know that
sec(90-0)=cosec0
given that
A+B=90*
=> A=(90*-B) ......... (1)
=> secA=5/3
secA(90*-B) =5/3 .....(1)sa
so.
cosecA=5/3
I hope it helps you
____swarnim__###
we know that
sec(90-0)=cosec0
given that
A+B=90*
=> A=(90*-B) ......... (1)
=> secA=5/3
secA(90*-B) =5/3 .....(1)sa
so.
cosecA=5/3
I hope it helps you
____swarnim__###
Similar questions