Math, asked by deshpandeshilpa6436, 1 year ago

If A+B=90 and Dec A = 5/3 then find the value of codec B

Answers

Answered by rohitkumargupta
9
HELLO DEAR,


we know that:-

sec(90-B)=cosecB

given that:-

A+B=90°

=> A= (90°-B)-------(1)


and


secA=5/3

=> sec(90-B)=5/3 --------from (1)

=> cosecA =5/3



I HOPE ITS HELP YOU DEAR,
THANKS
Answered by Anonymous
26
HAI DEAR!!

we know that

sec(90-0)=cosec0

given that

A+B=90*

=> A=(90*-B) ......... (1)

=> secA=5/3

secA(90*-B) =5/3 .....(1)sa

so.

cosecA=5/3

I hope it helps you

____swarnim__###
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