If A+B=90 and secA=5/3,then find the value of cosec B.
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a+b=90 seca =h/b 5/3 now
p=4 so you can 5/3+b=90
b=90-5/3
210-5/3 now u can solve it and b is 3/5 and cosecB=3/5
p=4 so you can 5/3+b=90
b=90-5/3
210-5/3 now u can solve it and b is 3/5 and cosecB=3/5
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