Question

If a+b=90 sina=3/4 then find the value of secb

Answer 1

a=90-b
punt a=90-b
sin (90-b)=3/4
cosb=3/4 since cos theta =1/sec theta
hence sec b =4/3

Answer 2

a+b=90°

a=90-b

sin a=3/4

sin(90°-b)=3/4

cosb=3/4

(Note-if sin=90°-b then cos must be b)

secb=4/3 (as it is the reciprocal of cosb)