If A + B =90°
sin A cosB + Cos A sin B
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A + B = 90
A = B - 90 ----------- I
In, sin(A)cos(B) + cos(A)sin(B) we substitute I
sin(-(90 - B))cos(B) + cos(-(90 - B))sin(B)
- cos(B)cos(B) + sin(B)sin(B)
(B) - (B)
- cos(2B)
Hence, the value of sin(A)cos(B) + cos(A)sin(B)
when, A + B = 90 is - cos(2B)
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