Math, asked by anandhika0606, 8 months ago

If A + B = 90°sinA 3 / 4 then secB is *


Answers

Answered by vaibhavsawate3pak0yn
0

Answer:here is the answer

Step-by-step explanation:

SinA=3/4

Sin (90-B)=3/4. ......given A+B=90

CosB= 3/4

Now reciprocol

secB =4/3

Answered by jaggajattjaggajatt44
0

Answer:

sec B=4/3

Step-by-step explanation:

A+B=90

A=90-B

sinA=3/4

sin(90-B)=3/4

cosB=3/4

secB=4/3

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