If A + B = 90°sinA 3 / 4 then secB is *
Answers
Answered by
0
Answer:
We have,
A + B = 90°
⇒ A = 90°- B
⇒ sin A = sin ( 90°- B ) [ sin (90 - θ) = cos θ ]
⇒ sin A = cos B
⇒ cos B = 3 / 4 [ sec θ = 1 / cos θ ]
⇒ sec B = 4 / 3
Similar questions