Math, asked by kvtulsi0505, 7 months ago

If A + B = 90°sinA 3 / 4 then secB is *


Answers

Answered by vsaneena34
0

Answer:

We have,

A + B = 90°

⇒ A = 90°- B

⇒ sin A = sin ( 90°- B ) [ sin (90 - θ) = cos θ ]

⇒ sin A = cos B

⇒ cos B = 3 / 4 [ sec θ = 1 / cos θ ]

⇒ sec B = 4 / 3

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