Question

if a-b,a,a+b are the zeros of the polynomial p(x)= x³+3x²-2 , then find the value of a+b/2a-b​

Answer 1

Answer:

Clearly, sum of the roots is,

a+(a-b)+(a+b)= -(-3)/1=3

=> 3a= 3

=> a= 1.

Again, product of roots is,

a(a-b)(a+b)= -1/1= -1

=>(1-b)(1+b) = -1 [since, a=1]

=> 1- b^2 = -1

=> b^2 = 2

=> b= √2, -√2

Thus, we get, a= 1 & b= √2, -√2.

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Answer 2

Answer:

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